Advertisements
Advertisements
प्रश्न
Explain the current flow in an NPN transistor.
Advertisements
उत्तर
- In NPN transistor electron flow from Emitter to the collector. So conventional current flow from collector to emitter.
- Electrons from the emitter region flow towards the base region constitute emitter current (IE). Electrons after reaching the base region recombine with holes – Most of the electrons reach the collector region. This constitutes collector current (IC). After recombination of holes in the base region by bias voltage VEE constitutes base current IB.
IE = IB + IC [Since base current is very low IC ≈ IC]
APPEARS IN
संबंधित प्रश्न
The common-base DC current gain of a transistor is 0.967. If the emitter current is 10mA. What is the value of base current?
In a common-base connection, a certain transistor has an emitter current of 10mA and a collector current of 9.8 mA. Calculate the value of the base current.
In a common-base connection, the emitter current is 6.28 mA and the collector current is 6.20 mA. Determine the common-base DC current gain.
For a transistor β =75 and IE = 7.5 mA. The value of α is ______
Draw the circuit symbol for NPN and PNP transistors. What is the difference in the Emitter, Base, and Collector regions of a transistor?
With the help of a neat diagram, explain the working of the npn transistor?
Give the Barkhausen conditions for sustained oscillations.
In switching circuit, transistor is in ON state. Values of IC and IB are 5.2 mA and 10 µA respectively and value of RC is 1 k`Omega`. If Vcc is at 5.5 V, then VCE is ______.
In case of npn transistors, the collector current is always less than the emitter current because ______.
Define α.
