Question

Explain by writing a reaction, which product will be formed on heating n - butyl alcohol with concentrated sulphuric acid.

Answer 1

One water molecule is removed from n-butyl alcohol when it is heated with strong sulphuric acid, forming 1-butene.

\[\ce{\underset{n-butyl alcohol}{CH3 - CH2} - CH2 - CH2 - OH ->[conc{.}H2SO4][Δ] \underset{1-butane}{CH3} - CH2 - CH = CH2 + H2O}\]