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प्रश्न
Explain by writing a reaction, which product will be formed on heating n - butyl alcohol with concentrated sulphuric acid.
रासायनिक समीकरणे/रचना
स्पष्ट करा
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उत्तर
One water molecule is removed from n-butyl alcohol when it is heated with strong sulphuric acid, forming 1-butene.
\[\ce{\underset{n-butyl alcohol}{CH3 - CH2} - CH2 - CH2 - OH ->[conc{.}H2SO4][Δ] \underset{1-butane}{CH3} - CH2 - CH = CH2 + H2O}\]
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