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Question
Expand the following:
(3 − 4ab)3
Sum
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Solution
Using the identity
(a − b)3 = a3 − 3ab(a − b) − b3
Here, let a = 3, b = 4ab
(3 − 4ab)3 = (3)3 − 3(3) (4ab)(3 − 4ab) − (4ab)3
= 27 − 9(4ab)(3 − 4ab) − 64a3b3
= 27 − 36ab(3 − 4ab) − 64a3b3
∴ (3 − 4ab)3 = 27 − 108ab − 144a2b2 − 64a3b3
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Chapter 3: Expansions - EXERCISE B [Page 35]
