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Question
Expand the following:
`(1/x + y/3)^3`
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Solution
`(1/x + y/3)^3 = (1/x)^3 + (y/3)^3 + 3(1/x)(y/3)(1/x + y/3)` ...[Using identity, (a + b)3 = a3 + b3 + 3ab(a + b)]
= `1/x^3 + y^3/27 + y/x(1/x + y/3)`
= `1/x^3 + y^3/27 + y/x^2 + y^2/(3x)`
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