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Question
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`("p"/3 + "q"/4)^2`
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Solution
`("p"/3 + "q"/4)^2`
Using the identity (a + b)2
= a2 + 2ab + b2
= `("p"/3)^2 + 2 xx "p"/3 xx "q"/4 + ("q"/4)^2`
`= "p"^2/9 + "pq"/6 + "q"^2/16`
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