Advertisements
Advertisements
प्रश्न
Expand:
`("p"/3 + "q"/4)^2`
बेरीज
Advertisements
उत्तर
`("p"/3 + "q"/4)^2`
Using the identity (a + b)2
= a2 + 2ab + b2
= `("p"/3)^2 + 2 xx "p"/3 xx "q"/4 + ("q"/4)^2`
`= "p"^2/9 + "pq"/6 + "q"^2/16`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15.5: Miscellaneous Problems : Set 2 - Exercise [पृष्ठ १००]
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
(1.1m − 0.4) (1.1 m + 0.4)
Find the following squares by suing the identities
(0.4p − 0.5q)2
Using identities, evaluate 712
Using identities, evaluate 1022
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 5.1 × 5.2
Use the formula to find the value.
97 × 103
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 2x + 1
Factorise the following.
x2 + 9x + 20
Verify the following:
(7p – 13q)2 + 364pq = (7p + 13q)2
