Advertisements
Advertisements
प्रश्न
The sum of areas of two squares with sides 4a and 4b is ______.
Advertisements
उत्तर
The sum of areas of two squares with sides 4a and 4b is 16(a2 + b2).
Explanation:
∵ Area of a square = (Side)2
∴ Area of the square whose one side is 4a = (4a)2 = 16a2
Area of the square with side 4b = (4b)2 = 16b2
∴ Sum of areas = 16a2 + 16b2 = 16(a2 + b2)
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
`(2/3 m + 3/4 n)^2`
Simplify (2.5p − 1.5q)2 − (1.5p − 2.5q)2
Use an expansion formula to find the value.
(102)2
Use an expansion formula to find the value.
(97)2
Expand:
`("y" - 3/"y")^2`
Use a formula to multiply of (2a – 13)(2a + 13)
Expand: (51)2
Factorise the following using suitable identity
36m2 + 60m + 25
Simplify: (a + b)2 + (a – b)2
The cost of a chocolate is Rs (x + y) and Rohit bought (x + y) chocolates. Find the total amount paid by him in terms of x. If x = 10, find the amount paid by him.
