Advertisements
Advertisements
Question
The sum of areas of two squares with sides 4a and 4b is ______.
Advertisements
Solution
The sum of areas of two squares with sides 4a and 4b is 16(a2 + b2).
Explanation:
∵ Area of a square = (Side)2
∴ Area of the square whose one side is 4a = (4a)2 = 16a2
Area of the square with side 4b = (4b)2 = 16b2
∴ Sum of areas = 16a2 + 16b2 = 16(a2 + b2)
APPEARS IN
RELATED QUESTIONS
Use a suitable identity to get the following products.
(2y + 5) (2y + 5)
Simplify (m2 − n2m)2 + 2m3n2
Using identities, evaluate (5.2)2
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Expand:
`("y" - 3/"y")^2`
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 14x + 49
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
Verify the following:
(a + b)(a + b)(a + b) = a3 + 3a2b + 3ab2 + b3
Factorise `x^2 + 1/x^2 + 2 - 3x - 3/x`.
Find the length of the side of the given square if area of the square is 625 square units and then find the value of x.
