Advertisements
Advertisements
Question
The sum of areas of two squares with sides 4a and 4b is ______.
Advertisements
Solution
The sum of areas of two squares with sides 4a and 4b is 16(a2 + b2).
Explanation:
∵ Area of a square = (Side)2
∴ Area of the square whose one side is 4a = (4a)2 = 16a2
Area of the square with side 4b = (4b)2 = 16b2
∴ Sum of areas = 16a2 + 16b2 = 16(a2 + b2)
APPEARS IN
RELATED QUESTIONS
Use a suitable identity to get the following products.
(x + 3) (x + 3)
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Expand (5a + 6b)2
Expand: `("y" - 3/"y")^2`
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 2x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abx + b2
Factorise the following.
y2 + 18x + 65
Factorise the following.
y2 + 7y + 12
The area of a circle is given by the expression πx2 + 6πx + 9π. Find the radius of the circle.
The height of a triangle is x4 + y4 and its base is 14xy. Find the area of the triangle.
