Advertisements
Advertisements
प्रश्न
Expand: `("p"/3 + "q"/4)^2`
योग
Advertisements
उत्तर
`("p"/3 + "q"/4)^2`
Using the identity (a + b)2 = a2 + 2ab + b2
= `("p"/3)^2 + 2 xx "p"/3 xx "q"/4 + ("q"/4)^2`
`= "p"^2/9 + "pq"/6 + "q"^2/16`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
(b − 7)2
Simplify (a2 − b2)2
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 9.7 × 9.8
Use the formula to find the value.
502 × 498
Expand: (51)2
Simplify: (a + b)2 + (a – b)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 12x + 36
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x4 + 12x3 + 9x2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`x^2/4 + 2x + 4`
Factorise the following.
18 + 11x + x2
