Advertisements
Advertisements
प्रश्न
Expand:
(10 + y)2
योग
Advertisements
उत्तर
(10 + y)2
Using the identity (a + b)2 = a2 + 2ab + b2
= (10)2 + 2 × 10 × y + (y)2
= 100 + 20y + y2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15.5: Miscellaneous Problems : Set 2 - Exercise [पृष्ठ १००]
APPEARS IN
संबंधित प्रश्न
Simplify (ab + bc)2 − 2ab2c
Using identities, evaluate 9982
Using identities, evaluate 1.05 × 9.5
Expand `("a"/2+"b"/3)^2`
Expand (ax + by)2
Expand:
`("p"/3 + "q"/4)^2`
Using identity, find the value of (100.1)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2ax + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
The cost of a chocolate is Rs (x + y) and Rohit bought (x + y) chocolates. Find the total amount paid by him in terms of x. If x = 10, find the amount paid by him.
