Expand : ( 3a + 2/B )( 2a - 3/B )

Expand : `( 3a + 2/b )( 2a - 3/b )`

Sum

`( 3a + 2/b )( 2a - 3/b) = (3a)(2a) + ( 2/b )(2a) - (3/b)(3a) - (2/b)(3/b)`

= `6a^2 + ( 4/b - 9/b )a - 6/b^2`

= `6a^2 + (-5/b)a - 6/b^2`

= `6a^2 - [5a]/b - 6/b^2`

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Expansion of Formula

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (C) [Page 62]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (C) | Q 2.2 | Page 62

If a + b + c = 12 and a² + b² + c² = 50; find ab + bc + ca.

If a² + b² + c² = 50 and ab + bc + ca = 47, find a + b + c.

If x+ y - z = 4 and x² + y² + z² = 30, then find the value of xy - yz - zx.

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If a² + b² = 34 and ab = 12; find : 3(a + b)² + 5(a - b)²

If a² + b² = 34 and ab = 12; find : 7(a - b)² - 2(a + b)²

If 3x - `4/x` = 4; and x ≠ 0 find : 27x³ - `64/x^3`

Find the value of 'a': 9x² + (7a - 5)x + 25 = (3x + 5)²

If x = `1/[ 5 - x ] "and x ≠ 5 find "x^3 + 1/x^3`

If x = `1/( x - 5 ) "and x ≠ 5. Find" : x^2 - 1/x^2`