Expand: (2x-1x)(3x+2x) - Mathematics

Expand: `( 2x - 1/x )( 3x + 2/x )`

Sum

`( 2x - 1/x )( 3x + 2/x )`

= `2x( 3x + 2/x ) - 1/x( 3x + 2/x )`

= `6x^2 + 2x xx2/x-1/x xx3x-1/x xx2/x`

= `6x^2+4-3-2/x^2`

= `6x^2 + 1 - 2/x^2`

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Expansion of Formula

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (C) [Page 62]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (C) | Q 2.1 | Page 62

Expand : `( 3a + 2/b )( 2a - 3/b )`

Expand : ( x - 2y + 2 )²

Expand : `( x - 1/x + 5)^2`

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`[( x + 2y )^2]/(xy) + [(2y + 3z)^2]/(yz) + [(3z + x)^2]/(zx)`

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`a - 1/a`

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(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

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7x³ + 8x − `7/x^3 - 8/x`

If `(x^2 + 1)/x = 3 1/3` and x > 1; Find `x - 1/x`.

If 3a + 5b + 4c = 0, show that : 27a³ + 125b³ + 64c³ = 180 abc

If x = `1/[ 5 - x ] "and x ≠ 5 find "x^3 + 1/x^3`