Advertisements
Advertisements
Question
Expand : `(2"x"-1/(2"x"))^2`
Sum
Advertisements
Solution
`(2"x"-1/(2"x"))^2=(2"x")^2+(1/(2"x"))^2-2xx2"x"xx1/(2"x")`
`=4"x"^2+1/(4"x"^2)-2`
shaalaa.com
Important Formula of Expansion
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand: `("a"+1/(2"a"))^2`
Find the square of `2"m"^2-2/3"n"^2`
Find the square of `5"x"+1/(5"x")`
Find the square of `8"x"+3/2"y"`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If `"m" -1/"m"=5`, find: `"m"^4+1/"m"^4`
If a2 + b2 = 41 and ab = 4, find : a + b
If `2"a"+1/(2"a")=8`, find : `4"a"^2+1/(4"a"^2)`
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
Expand : (2a – 5b – 4c)2
