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Question
If `2"a"+1/(2"a")=8`, find : `4"a"^2+1/(4"a"^2)`
Sum
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Solution
`4"a"^2+1/(4"a"^2)=(2"a"+1/(2"a"))^2-2.2"a"1/(2"a")`
`(2"a"+1/(2"a"))^2-2`
= (8)2 − 2
= 64 − 2
= 62
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Important Formula of Expansion
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