Advertisements
Advertisements
Question
If `"m" -1/"m"=5`, find: `"m"^2-1/"m"^2`
Sum
Advertisements
Solution
`"m"^2-1/"m"^2=("m"+1/"m")("m"-1/"m")`
`=5("m"+1/"m")`
Now `("m"+1/"m")^2=("m"-1/"m")^2+4`
= (5)2 + 4
= 25 + 4
= 29
`∴"m"+1/"m"=sqrt29`
`∴"m"^2-1/"m"^2=(5)(sqrt29)=5sqrt29`
shaalaa.com
Important Formula of Expansion
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand : `(3"x"+1/(3"x"))^2`
Expand : `(2"x"-1/(2"x"))^2`
Find the square of `3"x"+2/"y"`
Find the square of `2"m"^2-2/3"n"^2`
Find the square of `5"x"+1/(5"x")`
Find the square of `8"x"+3/2"y"`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
Expand : (3x – 4y + 5z)2
Expand : (2a – 5b – 4c)2
