Advertisements
Advertisements
प्रश्न
If `"m" -1/"m"=5`, find: `"m"^2-1/"m"^2`
योग
Advertisements
उत्तर
`"m"^2-1/"m"^2=("m"+1/"m")("m"-1/"m")`
`=5("m"+1/"m")`
Now `("m"+1/"m")^2=("m"-1/"m")^2+4`
= (5)2 + 4
= 25 + 4
= 29
`∴"m"+1/"m"=sqrt29`
`∴"m"^2-1/"m"^2=(5)(sqrt29)=5sqrt29`
shaalaa.com
Important Formula of Expansion
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand : `(3"x"+1/(3"x"))^2`
Find the square of `"5a"/"6b"-"6b"/"5a"`
Find the square of `2"m"^2-2/3"n"^2`
Find the square of `5"x"+1/(5"x")`
Find the square of `8"x"+3/2"y"`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If a2 + b2 = 41 and ab = 4, find : a + b
If `2"a"+1/(2"a")=8`, find : `4"a"^2+1/(4"a"^2)`
If `2"a"+1/(2"a")=8`, find : `16"a"^4+1/(16"a"^4)`
Expand : (2a – 5b – 4c)2
