Advertisements
Advertisements
प्रश्न
If a2 + b2 = 41 and ab = 4, find : a – b
योग
Advertisements
उत्तर
(a − b)2 = a2 + b2 − 2ab
= 41 − 2(4)
= 41 − 8
= 33
∴ a − b = `sqrt33`
shaalaa.com
Application of Formulae
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
If a+b=5 and ab = 6, find a2 + b2
If a – b = 6 and ab = 16, find a2 + b2
If a2 + b2= 10 and ab = 3; find : a – b
If `"a" + 1/"a"=3`, find `"a"^2+1/"a"^2`
If `"a"^2+ 1/"a"^2=11`, find : `"a" -1/"a"`
If a + b + c = 10 and a2 + b2 + c2 = 38, find : ab + bc + ca
If a – b = 3 and ab = 10, find : a3 – b3.
Find : `"a"^3+1/"a"^3`, if `"a" +1/"a"=5`.
If `2"x"-1/(2"x")=4`, find : `4"x"^2+1/(4"x"^2)`
If `3"x"+1/(3"x")=3`, find : `9"x"^2+1/(9"x"^2)`
