Advertisements
Advertisements
प्रश्न
If 3x – 4y = 5 and xy = 3, find : 27x3 – 64y3.
Advertisements
उत्तर
27x3 – 64y3 = (3x)3 – (4y)3
= (3x − 4y)3 (3x − 4y)3 + 3 (3x) (4y) (3x − 4y) ......[ ∵ a3 − b3 = (a − b)3 + 3ab(a − b)]
= (5)3 + 36(xy) (3x − 4y)
= 125 + 36 (3) (5)
= 125 + 540
= 665
APPEARS IN
संबंधित प्रश्न
If a2 + b2= 10 and ab = 3; find : a + b
If a + b + c = 10 and a2 + b2 + c2 = 38, find : ab + bc + ca
Find: a2 + b2 + c2, if a + b + c = 9 and ab + bc + ca = 24
Find : a + b + c, if a2 + b2 + c2 = 83 and ab + bc + ca = 71.
If a + b = 6 and ab = 8, find: a3 + b3.
If a – b = 3 and ab = 10, find : a3 – b3.
If a + b + c = 9 and ab + bc + ca = 15, find: a2 + b2 + c2.
If a + b = 8 and ab = 15, find a3 + b3.
If 3x + 2y = 9 and xy = 3, find : 27x3 + 8y3.
The difference between the two numbers is 5 and their products are 14. Find the difference between their cubes.
