Advertisements
Advertisements
प्रश्न
Expand : `(2"x"-1/(2"x"))^2`
योग
Advertisements
उत्तर
`(2"x"-1/(2"x"))^2=(2"x")^2+(1/(2"x"))^2-2xx2"x"xx1/(2"x")`
`=4"x"^2+1/(4"x"^2)-2`
shaalaa.com
Important Formula of Expansion
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand : `(2"a"-1/"a")^2`
Find the square of `3"x"+2/"y"`
Find the square of `"5a"/"6b"-"6b"/"5a"`
Find the square of `2"m"^2-2/3"n"^2`
Find the square of `5"x"+1/(5"x")`
If a2 + b2 = 41 and ab = 4, find : a + b
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
Expand : (3x – 4y + 5z)2
Expand : (2a – 5b – 4c)2
