Advertisements
Advertisements
प्रश्न
Expand : `(2"a"-1/"a")^2`
योग
Advertisements
उत्तर
`(2"a"-1/"a")^2=(2"a")^2+(1/"a")^2-2xx2"a"xx1/"a"`
`=4"a"^2+1/"a"^2-4`
shaalaa.com
Important Formula of Expansion
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand: `("a"+1/(2"a"))^2`
Expand : `(2"x"-1/(2"x"))^2`
Find the square of `"5a"/"6b"-"6b"/"5a"`
Find the square of `2"m"^2-2/3"n"^2`
Find the square of `8"x"+3/2"y"`
If a2 + b2 = 41 and ab = 4, find : a + b
If `2"a"+1/(2"a")=8`, find : `16"a"^4+1/(16"a"^4)`
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
Expand : (3x – 4y + 5z)2
Expand : (2a – 5b – 4c)2
