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प्रश्न
Expand : `(2"a"-1/"a")^2`
योग
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उत्तर
`(2"a"-1/"a")^2=(2"a")^2+(1/"a")^2-2xx2"a"xx1/"a"`
`=4"a"^2+1/"a"^2-4`
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Important Formula of Expansion
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संबंधित प्रश्न
Expand : (a+b−c)2
Expand : `(2"x"-1/(2"x"))^2`
Find the square of `3"x"+2/"y"`
If `"a" +1/"a"=2`, find : `"a"^2+1/"a"^2`
If `"m" -1/"m"=5`, find: `"m"^4+1/"m"^4`
If `"m" -1/"m"=5`, find: `"m"^2-1/"m"^2`
If `2"a"+1/(2"a")=8`, find : `4"a"^2+1/(4"a"^2)`
If `3"x"-1/(3"x")=5`, find : `9"x"^2+1/(9"x"^2)`
If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
Expand : (3x – 4y + 5z)2
