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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Evaluate the following limits: limx→0tanx-sinxx3

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Question

Evaluate the following limits:

`lim_(x -> 0) (tan x - sin x)/x^3`

Sum
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Solution

We know `lim_(x -> 0) sinx/x` = 1

`lim_(x -> 0) (tan x - sin x)/x^3 =  lim_(x -> 0) (sinx/cosx - sin x)/x^3`

= `lim_(x -> 0) ((sinx - sinx cosx)/cosx)/x^3`

= `lim_(x -> 0) (sinx(1 -  cosx))/(x^3 cosx)`

= `lim_(x -> 0) sinx/x * (2sin^2 (x/2))/(x^2) xx 1/cosx`

= `lim_(x -> 0) sinx/x xx (2sin^2 (x/2))/(2^2 xx x^2/2^2) xx 1/cosx`

= `lim_(x -> 0) sinx/x xx 1/2 (lim_(x/2 -> 0) (sin(x/2))/(x/2))^2 xx lim_(x - 0) 1/cosx`

= `1 xx 1/2 xx 1^2 xx 1/cos0`

= `1/2 xx 1/1`

`lim_(x -> 0) (tan x - sin x)/x^3 = 1/2`

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Chapter 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [Page 118]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 28 | Page 118

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