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Evaluate sin18°/cos72° - Mathematics

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Question

Evaluate `(sin 18^@)/(cos 72^@)`

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Solution

`(sin 18^@)/(cos72^@) = (sin(90^@ - 72^@))/cos 72^@`

`= (cos 72^@)/(cos 72^@) = 1`

 

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Chapter 8: Introduction to Trigonometry - Exercise 8.3 [Page 189]

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NCERT Mathematics [English] Class 10
Chapter 8 Introduction to Trigonometry
Exercise 8.3 | Q 1.1 | Page 189
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