Advertisements
Advertisements
Question
Evaluate:
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
Advertisements
Solution
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
= `[cot(90^circ - 49^circ)]^2/(tan^2 49^circ) - 2 [sin(90^circ - 15^circ)]^2/cos^2 15^circ`
= `tan^2 49^circ/(tan^2 49^circ) - 2 cos^2 15^circ/cos^2 15^circ`
= 1 – 2
= – 1
APPEARS IN
RELATED QUESTIONS
`\text{Evaluate }\frac{\tan 65^\circ }{\cot 25^\circ}`
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Use tables to find cosine of 9° 23’ + 15° 54’
Use tables to find the acute angle θ, if the value of tan θ is 0.2419
If 4 cos2 A – 3 = 0 and 0° ≤ A ≤ 90°, then prove that cos 3 A = 4 cos3 A – 3 cos A
If the angle θ = –45° , find the value of tan θ.
If A + B = 90° and \[\tan A = \frac{3}{4}\]\[\tan A = \frac{3}{4}\] what is cot B?
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
Find the value of the following:
`((cos 47^circ)/(sin 43^circ))^2 + ((sin 72^circ)/(cos 18^circ))^2 - 2cos^2 45^circ`
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.

