Advertisements
Advertisements
Question
Evaluate:
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
Advertisements
Solution
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
= `[cot(90^circ - 49^circ)]^2/(tan^2 49^circ) - 2 [sin(90^circ - 15^circ)]^2/cos^2 15^circ`
= `tan^2 49^circ/(tan^2 49^circ) - 2 cos^2 15^circ/cos^2 15^circ`
= 1 – 2
= – 1
APPEARS IN
RELATED QUESTIONS
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
if `sqrt3 tan theta = 3 sin theta` find the value of `sin^2 theta - cos^2 theta`
Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
Use tables to find cosine of 9° 23’ + 15° 54’
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
If 3 cos θ = 5 sin θ, then the value of
The value of cos 1° cos 2° cos 3° ..... cos 180° is
In the following figure the value of cos ϕ is
If ∠A = 30°, then tan 2A = ?
