Advertisements
Advertisements
प्रश्न
Evaluate:
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
Advertisements
उत्तर
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
= `[cot(90^circ - 49^circ)]^2/(tan^2 49^circ) - 2 [sin(90^circ - 15^circ)]^2/cos^2 15^circ`
= `tan^2 49^circ/(tan^2 49^circ) - 2 cos^2 15^circ/cos^2 15^circ`
= 1 – 2
= – 1
संबंधित प्रश्न
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
Prove the following trigonometric identities.
(cosecA − sinA) (secA − cosA) (tanA + cotA) = 1
For triangle ABC, show that : `sin (A + B)/2 = cos C/2`
Use tables to find sine of 21°
Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)
If \[\tan \theta = \frac{4}{5}\] find the value of \[\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta}\]
If \[\cos \theta = \frac{2}{3}\] find the value of \[\frac{\sec \theta - 1}{\sec \theta + 1}\]
If θ is an acute angle such that sec2 θ = 3, then the value of \[\frac{\tan^2 \theta - {cosec}^2 \theta}{\tan^2 \theta + {cosec}^2 \theta}\]
If x tan 45° sin 30° = cos 30° tan 30°, then x is equal to ______.
If A, B and C are interior angles of a ΔABC then `cos (("B + C")/2)` is equal to ______.
