Advertisements
Advertisements
Question
Use tables to find the acute angle θ, if the value of tan θ is 0.2419
Advertisements
Solution
From the tables, it is clear that tan 13° 36’ = 0.2419
Hence, θ = 13° 36’
RELATED QUESTIONS
If the angle θ= –60º, find the value of cosθ.
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
Write all the other trigonometric ratios of ∠A in terms of sec A.
Solve.
`cos55/sin35+cot35/tan55`
Evaluate:
3 cos 80° cosec 10° + 2 cos 59° cosec 31°
Prove that:
`1/(1 + cos(90^@ - A)) + 1/(1 - cos(90^@ - A)) = 2cosec^2(90^@ - A)`
Given
\[\frac{4 \cos \theta - \sin \theta}{2 \cos \theta + \sin \theta}\] what is the value of \[\frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta}\]
If 5 tan θ − 4 = 0, then the value of \[\frac{5 \sin \theta - 4 \cos \theta}{5 \sin \theta + 4 \cos \theta}\] is:
A triangle ABC is right-angled at B; find the value of `(sec "A". sin "C" - tan "A". tan "C")/sin "B"`.
If cot( 90 – A ) = 1, then ∠A = ?
