Advertisements
Advertisements
Question
Prove that:
`(cos(90^circ - theta)costheta)/cottheta = 1 - cos^2theta`
Advertisements
Solution
L.H.S. = `(cos(90^circ - theta)costheta)/cottheta`
= `(sinthetacostheta)/(costheta/sintheta)`
= `(sinthetacostheta xx sintheta)/costheta`
= sin2θ
= 1 – cos2θ = R.H.S.
RELATED QUESTIONS
if `cot theta = sqrt3` find the value of `(cosec^2 theta + cot^2 theta)/(cosec^2 theta - sec^2 theta)`
Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`
Use tables to find sine of 34° 42'
Use tables to find cosine of 2° 4’
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Find A, if 0° ≤ A ≤ 90° and 4 sin2 A – 3 = 0
If 5θ and 4θ are acute angles satisfying sin 5θ = cos 4θ, then 2 sin 3θ −\[\sqrt{3} \tan 3\theta\] is equal to
A triangle ABC is right-angled at B; find the value of `(sec "A". sin "C" - tan "A". tan "C")/sin "B"`.
Prove that `"tan A"/"cot A" = (sec^2"A")/("cosec"^2"A")`
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
