Advertisements
Advertisements
Question
Prove that:
`(cos(90^circ - theta)costheta)/cottheta = 1 - cos^2theta`
Advertisements
Solution
L.H.S. = `(cos(90^circ - theta)costheta)/cottheta`
= `(sinthetacostheta)/(costheta/sintheta)`
= `(sinthetacostheta xx sintheta)/costheta`
= sin2θ
= 1 – cos2θ = R.H.S.
APPEARS IN
RELATED QUESTIONS
if `tan theta = 3/4`, find the value of `(1 - cos theta)/(1 +cos theta)`
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
Find the value of x, if sin 2x = 2 sin 45° cos 45°
Use tables to find the acute angle θ, if the value of tan θ is 0.2419
If \[\tan \theta = \frac{1}{\sqrt{7}}, \text{ then } \frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta} =\]
The value of cos2 17° − sin2 73° is
Find the value of the following:
sin 21° 21′
The value of cosec(70° + θ) – sec(20° − θ) + tan(65° + θ) – cot(25° − θ) is
The value of (tan1° tan2° tan3° ... tan89°) is ______.
