Advertisements
Advertisements
Question
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
Advertisements
Solution
`(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
= `cos(90° - 35°)/(sin 35°) + cot(90° - 55°)/(tan 55°)`
= `(sin 35°)/(sin 35°) + (tan 55°)/(tan 55°)`
= 1 + 1
= 2
APPEARS IN
RELATED QUESTIONS
Without using trigonometric tables, evaluate the following:
`(\sin ^{2}20^\text{o}+\sin^{2}70^\text{o})/(\cos ^{2}20^\text{o}+\cos ^{2}70^\text{o}}+\frac{\sin (90^\text{o}-\theta )\sin \theta }{\tan \theta }+\frac{\cos (90^\text{o}-\theta )\cos \theta }{\cot \theta }`
Solve.
`sec75/(cosec15)`
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
Evaluate:
`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
What is the maximum value of \[\frac{1}{\sec \theta}\]
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
Evaluate: cos2 25° - sin2 65° - tan2 45°
Evaluate: `(sin 80°)/(cos 10°)`+ sin 59° sec 31°
The value of tan 72° tan 18° is
