Advertisements
Advertisements
Question
Evaluate : (3x−4y) (3x+4y) (9x2+16y2)
Sum
Advertisements
Solution
(3x−4y) (3x+4y) (9x2+16y2)
= [(3x)2−(4y)2] (9x2+16y2)
= (9x2−16y2) (9x2+16y2)
= (9x2)2 − (16y2)2
= 81x4 − 256y4
shaalaa.com
Product of Sum and Difference of Two Terms
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Use the product (a + b) (a – b) = a2 – b2 to evaluate:
21 x 19
Use the product (a + b) (a – b) = a2 – b2 to evaluate:
33 x 27
Use the product (a + b) (a – b) = a2 – b2 to evaluate:
7.7 x 8.3
Evaluate : `(7"x"+2/3"y")(7"x"-2/3"y")`
Evaluate : `(3"x"-1/(2"y"))(3"x"+1/(2"y"))`
Evaluate : (a + bc) (a − bc) (a2 + b2c2)
Evaluate : (7x + 15y) (5x − 4y)
Evaluate: (a2 + 5) (a2 − 3)
Evaluate: (3x + 4y) (3x − 4y) (9x2 + 16y2)
Evaluate: (a + bc) (a − bc) (a2 + b2c2)
