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प्रश्न
Evaluate : (3x−4y) (3x+4y) (9x2+16y2)
योग
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उत्तर
(3x−4y) (3x+4y) (9x2+16y2)
= [(3x)2−(4y)2] (9x2+16y2)
= (9x2−16y2) (9x2+16y2)
= (9x2)2 − (16y2)2
= 81x4 − 256y4
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Product of Sum and Difference of Two Terms
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