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प्रश्न
Evaluate: (2a + 3) (2a − 3) (4a2 + 9)
योग
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उत्तर
(2a + 3) (2a − 3) (4a2 + 9)
= [(2a)2 − (3)2] (4a2 + 9) ...[(a + b) (a − b) = a2 − b2]
= (4a2 − 9) (4a2 + 9)
= (4a2)2 − (9)2 ...[(a + b) (a − b) = a2 − b2]
= 16a4 − 81
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Product of Sum and Difference of Two Terms
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