Advertisements
Advertisements
प्रश्न
Evaluate : (3x−4y) (3x+4y) (9x2+16y2)
बेरीज
Advertisements
उत्तर
(3x−4y) (3x+4y) (9x2+16y2)
= [(3x)2−(4y)2] (9x2+16y2)
= (9x2−16y2) (9x2+16y2)
= (9x2)2 − (16y2)2
= 81x4 − 256y4
shaalaa.com
Product of Sum and Difference of Two Terms
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Use the product (a + b) (a – b) = a2 – b2 to evaluate:
21 x 19
Use the product (a + b) (a – b) = a2 – b2 to evaluate:
33 x 27
Evaluate : `("a"/(2"b")+(2"b")/"a")("a"/(2"b")-(2"b")/"a")`
Evaluate : `(3"x"-1/(2"y"))(3"x"+1/(2"y"))`
Evaluate: (2a + 3) (2a − 3) (4a2 + 9)
Evaluate : (a + bc) (a − bc) (a2 + b2c2)
Evaluate : (2a − 3b) (3a + 4b)
Evaluate: (4x2 − 5y2) (4x2 + 5y2)
Evaluate: (3x + 4y) (3x − 4y) (9x2 + 16y2)
Evaluate: (a + bc) (a − bc) (a2 + b2c2)
