Advertisements
Advertisements
Question
Evaluate: `(2"a"+1/"2a")(2"a"-1/"2a")`
Advertisements
Solution
`(2"a"+1/"2a")(2"a"-1/"2a")`
`=(2"a")^2-(1/"2a")^2` ......[ ∵ (a − b) (a + b) = a2b2]
`=4"a"^2-1/"4a"^2`
APPEARS IN
RELATED QUESTIONS
Simplify the following products:
`(1/2a - 3b)(1/2a + 3b)(1/4a^2 + 9b^2)`
Prove that a2 + b2 + c2 − ab − bc − ca is always non-negative for all values of a, b and c
Write in the expand form: `(2x - y + z)^2`
Simplify of the following:
(x+3)3 + (x−3)3
The difference between two positive numbers is 5 and the sum of their squares is 73. Find the product of these numbers.
Use the direct method to evaluate :
(ab+x2) (ab−x2)
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" - (1)/"a"`
If `"r" - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`
Simplify:
(x + 2y + 3z)(x2 + 4y2 + 9z2 - 2xy - 6yz - 3zx)
Expand the following:
(–x + 2y – 3z)2
