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Question
Draw the orbital diagram of `""_20^40"Ca"^(2+)` ion and state the number of three fundamental particles present in it.
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Solution
Neutral calcium (Z = 20) has
1s22s22p63s23p64s2
For Ca2+, remove 2 electrons from the outermost 4s orbital:
1s22s22p63s23p6
it has 18 electrons
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Protons = 20
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Neutrons = 20
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Electrons = 18
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