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Draw the orbital diagram of 4020⁢Ca2+ ion and state the number of three fundamental particles present in it.

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Question

Draw the orbital diagram of `""_20^40"Ca"^(2+)` ion and state the number of three fundamental particles present in it.

Diagram
Short Answer
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Solution

Neutral calcium (Z = 20) has

1s22s22p63s23p64s2

For Ca2+, remove 2 electrons from the outermost 4s orbital:

1s22s22p63s23p6

it has 18 electrons

  • Protons = 20

  • Neutrons = 20

  • Electrons = 18

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Chapter 4: Atomic Structure and Chemical Bonding - Exercise 4 (B) [Page 63]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 4 Atomic Structure and Chemical Bonding
Exercise 4 (B) | Q 9 | Page 63

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With the help of given Table, find out the mass number of sulphur atom.

Composition of Atoms of the First Eighteen Elements with Electron Distribution in Various Shells
Name of Element Symbol Atomic Number Number of protons Number of Neutrons Number of Electrons Distribution of Electrons Valency
K L M N
Hydrogen H 1 1 - 1 1 - - - 1
Helium He 2 2 2 2 2 - - - 0
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Boron B 5 5 6 5 2 3 - - 3
Carbon C 6 6 6 6 2 4 - - 4
Nitrogen N 7 7 7 7 2 5 - - 3
Oxygen O 8 8 8 8 2 6 - - 2
Fluorine F 9 9 10 9 2 7 - - 1
Neon Ne 10 10 10 10 2 8 - - 0
Sodium Na 11 11 12 11 2 8 1 - 1
Magnesium Mg 12 12 12 12 2 8 2 - 2
Aluminium Al 13 13 14 13 2 8 3 - 3
Silicon Si 14 14 14 14 2 8 4 - 4
Phosphorus P 15 15 16 15 2 8 5 - 3.5
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Chlorine Cl 17 17 18 17 2 8 7 - 1
Argon Ar 18 18 22 18 2 8 8   0

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