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प्रश्न
Draw the orbital diagram of `""_20^40"Ca"^(2+)` ion and state the number of three fundamental particles present in it.
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उत्तर
Neutral calcium (Z = 20) has
1s22s22p63s23p64s2
For Ca2+, remove 2 electrons from the outermost 4s orbital:
1s22s22p63s23p6
it has 18 electrons
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Protons = 20
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Neutrons = 20
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Electrons = 18
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Calcium – \[\ce{^40_20Ca}\]
[The upper number represent the – mass number and the lower number represent the – atomic number e.g. calcium – mass number = 40, atomic number = 20]
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Match the following:
| Column A | Column B | ||
| 1. | Mass of proton | a. | +1 |
| 2. | Mass of electron | b. | -1 |
| 3. | Charge of electron | c. | 9.31 x 10-28g |
| 4. | Charge of proton | d. | 1.67 x 10-24g |
