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प्रश्न
Draw the orbital diagram of `""_20^40"Ca"^(2+)` ion and state the number of three fundamental particles present in it.
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उत्तर
Neutral calcium (Z = 20) has
1s22s22p63s23p64s2
For Ca2+, remove 2 electrons from the outermost 4s orbital:
1s22s22p63s23p6
it has 18 electrons
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Protons = 20
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Neutrons = 20
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Electrons = 18
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संबंधित प्रश्न
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| X | Y | |
| Protons | 6 | 6 |
| Neutrons | 6 | 8 |
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Match the following:
| Column A | Column B | ||
| 1. | K shell | a. | 8 |
| 2. | L shell | b. | 32 |
| 3. | M shell | c. | 2 |
| 4. | N shell | d. | 18 |
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What is its atomic number?
