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प्रश्न
Draw the orbital diagram of `""_20^40"Ca"^(2+)` ion and state the number of three fundamental particles present in it.
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उत्तर

Neutral calcium (Z = 20) has
1s22s22p63s23p64s2
For Ca2+, remove 2 electrons from the outermost 4s orbital:
1s22s22p63s23p6
it has 18 electrons
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Protons = 20
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Neutrons = 20
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Electrons = 18
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संबंधित प्रश्न
Complete the following table.
| Atomic number | Mass number | Number of Neutrons | Number of protons | Number of electrons | Name of the Atomic species |
| 9 | - | 10 | - | - | - |
| 16 | 32 | - | - | - | Sulphur |
| - | 24 | - | 12 | - | - |
| - | 2 | - | 1 | - | - |
| - | 1 | 0 | 1 | 0 | - |
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