Advertisements
Advertisements
Question
Draw the M.O diagram for oxygen molecule calculate its bond order and show that O2 is paramagnetic.
Advertisements
Solution
MO Diagram for O2 molecule
Electronic configuration of O atom:
1s2 2s2 2p4
Electronic configuration of O2 molecule:
σ1s2, σ1s*2, σ2s2, σ2s*2, σ2px2, π2py2 π2pz2 π2py*1 π2pz*1
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 6)/2`
= 2
The molecule has two unpaired electrons hence it is paramagnetic.
APPEARS IN
RELATED QUESTIONS
Give the total number of electrons around sulfur (S) in SF6 compound.
Why is O2 molecule paramagnetic?
Pick out the incorrect statement from the following:
Discuss the formation of N2 molecule using MO Theory.
Hydrogen gas is diatomic whereas inert gases are monoatomic – Explain on the basis of MO theory.
Which one of the following sets CORRECTLY represents the increase in the paramagnetic property of the ions?
Among the following MOs, the highest energy MO that is occupied by electrons in case of N2 molecule is ______.
According to molecular orbital theory, antibonding molecular orbitals of O2 contain ____________.
The electronic configuration of Be2 molecule according MOT is ______.
Which element among the following does not form diatomic molecules?
