Advertisements
Advertisements
प्रश्न
Draw the M.O diagram for oxygen molecule calculate its bond order and show that O2 is paramagnetic.
Advertisements
उत्तर
MO Diagram for O2 molecule
Electronic configuration of O atom:
1s2 2s2 2p4
Electronic configuration of O2 molecule:
σ1s2, σ1s*2, σ2s2, σ2s*2, σ2px2, π2py2 π2pz2 π2py*1 π2pz*1
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 6)/2`
= 2
The molecule has two unpaired electrons hence it is paramagnetic.
APPEARS IN
संबंधित प्रश्न
Select and write the most appropriate alternatives from the given choices.
Which O2 molecule is paramagnetic. It is explained on the basis of ______.
Why is O2 molecule paramagnetic?
Assertion: Oxygen molecule is paramagnetic.
Reason: It has two unpaired electron in its bonding molecular orbital.
Of the following molecules, which have shape similar to carbon dioxide?
CaO and NaCl have the same crystal structure and approximately the same radii. If U is the lattice energy of NaCl, the approximate lattice energy of CaO is ______.
Draw MO diagram of CO and calculate its bond order.
According to molecular orbital theory, which of the following will NOT be viable?
H2 molecule is more stable than Li2 molecule, because ______.
Which of the following molecules has bond order zero?
Given below are two statements:
Statement I: A hypothetical diatomic molecule with bond order zero is quite stable.
Statement II: As bond order increases, the bond length increases. In the light of the above statements, chose the most appropriate answer from the options given below:
