Advertisements
Advertisements
प्रश्न
Draw MO diagram of CO and calculate its bond order.
Advertisements
उत्तर
Bonding in some hetero nuclear di-atomic molecules:
Molecular orbital diagram of Carbon monoxide molecule (CO)
Electronic configuration of C atom: 1s2 2s2 2p2
Electronic configuration of O atom: 1s2 2s2 2p4
Electronic configuration of CO molecule :
σ1s2, σ1s*2, σ2s2, σ2s*2, π2py2, π2pz2 σ2px2
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 4)/2` = 3
The molecule has no unpaired electrons hence it is diamagnetic.
APPEARS IN
संबंधित प्रश्न
Select and write the most appropriate alternatives from the given choices.
Which of the following is true for CO2?
Draw an orbital diagram of Hydrogen fluoride molecule
Give the total number of electrons around sulfur (S) in SF6 compound.
Pick out the incorrect statement from the following:
Hydrogen gas is diatomic whereas inert gases are monoatomic – Explain on the basis of MO theory.
Among the following MOs, the highest energy MO that is occupied by electrons in case of N2 molecule is ______.
The electronic configuration of Be2 molecule according MOT is ______.
The correct statement with regard to \[\ce{H^+_2}\] and \[\ce{H^-_2}\] is:
Which element among the following does not form diatomic molecules?
What is the number of unpaired electrons present in O2 molecule?
