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Maharashtra State BoardSSC (English Medium) 9th Standard

Divide the first polynomial by the second polynomial and find the remainder using remainder theorem. (54m3 + 18m2 − 27m + 5) ; (m − 3)

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Question

Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.

(54m3 + 18m2 − 27m + 5) ; (m − 3)

Sum
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Solution

p(x) = 54m3 + 18m2 − 27m + 5

Divisor = m − 3

∴ take m = 3

By remainder theorem, 

Remainder = p(3)

54 × (3)3 + 18 × (3)3 − 27 × 3 + 5

= 54 × 27 + 18 × 9 − 27 × 3 + 5

= 1458 + 162 - 81 + 5

= 1544

∴ Remainder = 1544

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Chapter 3: Polynomials - Practice Set 3.5 [Page 53]

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Balbharati Mathematics 1 [English] Standard 9 Maharashtra State Board
Chapter 3 Polynomials
Practice Set 3.5 | Q (5) (iii) | Page 53

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