English

Distinguish Between Nuclear Fission and Fusion.

Advertisements
Advertisements

Question

Distinguish between nuclear fission and fusion. Show how in both these processes energy is released. Calculate the energy release in MeV in the deuterium-tritium fusion reaction :

`""_1^2H+_1^3H->_2^4He+n`

Using the data :

m(`""_1^2H`) = 2.014102 u

m(`""_1^3H`) = 3.016049 u

m(`""_2^4He`) = 4.002603 u

mn = 1.008665 u

1u = 931.5 MeV/c2

Advertisements

Solution

Nuclear fission: It is the phenomenon of splitting of a heavy nucleus (usually A > 230) into two or more lighter nuclei.

`""_92U^235+_0n^1->_56Ba^141+_36Kr^92+3_0n^1+Q`

Here, the energy released per fission of `""_92U^235` is 200.4 MeV.

Nuclear fusion: It is the phenomenon of fusion of two or more lighter nuclei to form a single heavy nucleus.

The mass of the product nucleus is slightly less than the sum of the masses of the lighter nuclei fusing together. This difference in masses results in the release of tremendous amount of energy.

Example:

`""_1H^1+_1H^1->_1H^2+e^++v+0.42 MeV`

`""_1H^2+_1H^2->_2He^3+n+3.27MeV`

`""_1H^2+_1H^2->_1H^3+_1H^1+4.03MeV`

`""_1^2H+_1^3H->_2^4He+n`

 Δm = (2.014102 + 3.016049)  (4.002603 + 1.008665 )

=0.018883 u

Energy released, Q = 0.018883 × 931.5 `MeV"/"_(c^2`

= 17.589 MeV

shaalaa.com
  Is there an error in this question or solution?
2014-2015 (March) Delhi Set 2

Video TutorialsVIEW ALL [2]

RELATED QUESTIONS

In a photon-electron collision ______.
(A) only total energy is conserved.
(B) only total momentum is conserved.
(C) both total energy and total momentum are conserved.
(D) both total momentum and total energy are not conserved


Calculate the height of the potential barrier for a head on collision of two deuterons.

(Hint: The height of the potential barrier is given by the Coulomb repulsion between the two deuterons when they just touch each other. Assume that they can be taken as hard spheres of radius 2.0 fm.)


Write notes on Nuclear fission


Write notes on Nuclear fusion


 In a nuclear reaction

`"_2^3He + _2^3He -> _2^4He +_1^1H +_1^1H + 12.86 Me V` though the number of nucleons is conserved on both sides of the reaction, yet the energy is released. How? Explain.


Calculate the Q-values of the following fusion reactions :-

(a) `""_1^2H + ""_1^2H → ""_1^3H + ""_1^1H`

(b) `""_1^2H + ""_1^2H → ""_2^3H + n`

(c) `""_1^2H + ""_1^3H → _2^4H + n`.

Atomic masses are `m(""_1^2H) = 2.014102 "u", m(""_1^3H) = 3.016049 "u", m(""_2^3He) = 3.016029 "u", m(""_2^4He) = 4.002603 "u".`

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)


Why nuclear fusion reaction is also called thermo-nuclear reaction?


In our Nature, where is the nuclear fusion reaction taking place continuously?


A slab of stone of area 0.36 m2 and thickness 0.1 m is exposed on the lower surface to steam at 100°C. A block of ice at 0°C rests on the upper surface of the slab. In one hour 4.8 kg of ice is melted. The thermal conductivity of the slab is:
(Given latent heat of fusion of ice = 3.36 × 105 J kg−1)


How long can an electric lamp of 1000 W be kept glowing by fusion of 2.0 kg of deuterium? Take the fusion reaction as:

\[{}_{1}^{2}\mathrm{H}+{}_{1}^{2}\mathrm{H}\rightarrow{}_{2}^{3}\mathrm{He}+\mathrm{n}+3.27\mathrm{MeV}\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×