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Differentiate Sin − 1 { X √ X 2 + a 2 } ? - Mathematics

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Question

Differentiate \[\sin^{- 1} \left\{ \frac{x}{\sqrt{x^2 + a^2}} \right\}\] ?

Sum
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Solution

\[\text{ Let, y }= \sin^{- 1} \left\{ \frac{x}{\sqrt{x^2 + a^2}} \right\}\]

\[\text{put x } = a \tan\theta\]

\[ \Rightarrow y = \sin^{- 1} \left\{ \frac{a \tan\theta}{\sqrt{a^2 \tan^2 \theta + a^2}} \right\}\]

\[ \Rightarrow y = \sin^{- 1} \left\{ \frac{a \tan\theta}{\sqrt{a^2 \left( \tan^2 \theta + 1 \right)}} \right\}\]

\[ \Rightarrow y = \sin^{- 1} \left( \frac{a \tan\theta}{a sec\theta} \right) \]

\[ \Rightarrow y = \sin^{- 1} \left( \sin\theta \right) \]

\[ \Rightarrow y = \theta\]

\[ \Rightarrow y = \tan^{- 1} \left( \frac{x}{a} \right) \left[ \text{since, }x = a \tan\theta \right] \]

\[\text{ Differentiating it with respect to x using chain rule }, \]

\[ \frac{d y}{d x} = \frac{1}{1 + \left( \frac{x}{a} \right)^2}\frac{d}{dx}\left( \frac{x}{a} \right)\]

\[ \Rightarrow \frac{d y}{d x} = \frac{a^2}{a^2 + x^2} \times \left( \frac{1}{a} \right)\]

\[ \therefore \frac{d y}{d x} = \frac{a}{a^2 + x^2}\]

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Chapter 11: Differentiation - Exercise 11.03 [Page 63]

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RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.03 | Q 6 | Page 63

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