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Differentiate x1/x with respect to x. - Mathematics

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Question

Differentiate \[x^{1/x}\]  with respect to x.

Sum
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Solution

Let `y=x^(1/x)`

Take the natural logarithm of both sides: `log y = 1/x log x`

Differentiating log y gives:

`1/y dy/dx = d/dx (log x/x)`

`d/dx (log x/x)=((1/x)xxx-logxxx1)/x^2`

`1/y dy/dx = (1-logx)/x^2`

Multiply through by y to isolate `dy/dx`

`dy/dx = yxx (1-logx)/x^2`

Substitute y = x1/x back into the equation:

`dy/dx = x^(1/x) xx (1-logx)/x^2`

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Chapter 11: Differentiation - Exercise 11.05 [Page 88]

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RD Sharma Mathematics [English] Class 12
Chapter 11 Differentiation
Exercise 11.05 | Q 1 | Page 88

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