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Question
Differentiate \[e^{\cos x}\] with respect to \[x\].
Options
\[(\sin x)e^{\cos x}\]
\[(\cos x)e^{\sin x}\]
\[-e^{\sin x}\]
\[-(\sin x)e^{\cos x}\]
MCQ
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Solution
Apply the chain rule to \[e^{\cos x}\]. The derivative of \[\cos x\] is \[-\sin x\], giving \[-(\sin x)e^{\cos x}\].
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