Advertisements
Advertisements
प्रश्न
Differentiate \[e^{\cos x}\] with respect to \[x\].
विकल्प
\[(\sin x)e^{\cos x}\]
\[(\cos x)e^{\sin x}\]
\[-e^{\sin x}\]
\[-(\sin x)e^{\cos x}\]
MCQ
Advertisements
उत्तर
Apply the chain rule to \[e^{\cos x}\]. The derivative of \[\cos x\] is \[-\sin x\], giving \[-(\sin x)e^{\cos x}\].
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
