Advertisements
Advertisements
Question
Determine the sum of first 100 terms of given A.P. 12, 14, 16, 18, 20,......
Activity :- Here, a = 12, d = `square`, n = 100, S100 = ?
Sn = `"n"/2 [square + ("n" - 1)"d"]`
S100 = `square/2 [24 + (100 - 1)"d"]`
= `50(24 + square)`
= `square`
= `square`
Advertisements
Solution
Here, a = 12, d = 14 – 12 = \[\boxed{2}\], n = 100, S100 = ?
Sn = \[\frac{\text{n}}{2} [\boxed{\text{2a}} + (\text{n} - 1)\text{d}]\]
S100 = \[\frac{\boxed{100}}{2} [24 + (100 - 1)\text{d}]\]
= 50[24 + 99(2)]
= \[50(24 + \boxed{198})\]
= \[\boxed{50(222)}\]
= \[\boxed{11100}\]
APPEARS IN
RELATED QUESTIONS
Find four numbers in A.P. whose sum is 20 and the sum of whose squares is 120
How many multiples of 4 lie between 10 and 250?
Find the sum of the following APs:
2, 7, 12, ..., to 10 terms.
Find the sum of the following APs.
0.6, 1.7, 2.8, …….., to 100 terms.
In an AP given a = 3, n = 8, Sn = 192, find d.
Find the 12th term from the end of the following arithmetic progressions:
3, 5, 7, 9, ... 201
Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667.
The first term of an A.P. is 5, the last term is 45 and the sum of its terms is 1000. Find the number of terms and the common difference of the A.P.
A sum of ₹2800 is to be used to award four prizes. If each prize after the first is ₹200 less than the preceding prize, find the value of each of the prizes
What is the 5th term form the end of the AP 2, 7, 12, …., 47?
Write the next term of the AP `sqrt(2) , sqrt(8) , sqrt(18),.........`
If the sum of n terms of an A.P. be 3n2 + n and its common difference is 6, then its first term is ______.
If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164?
The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is
If Sn denote the sum of n terms of an A.P. with first term a and common difference dsuch that \[\frac{Sx}{Skx}\] is independent of x, then
The sum of first n terms of an A.P. whose first term is 8 and the common difference is 20 equal to the sum of first 2n terms of another A.P. whose first term is – 30 and the common difference is 8. Find n.
Shubhankar invested in a national savings certificate scheme. In the first year he invested ₹ 500, in the second year ₹ 700, in the third year ₹ 900 and so on. Find the total amount that he invested in 12 years.
The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms.
If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256, find the sum of first 10 terms.
Find the sum of first 'n' even natural numbers.
