Advertisements
Advertisements
Question
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
Advertisements
Solution
| Element | Atomic mass | Percentage | Relative number of moles | Simplest mole ratio | Whole number ratio |
| N | 14 | 42 | 42/14 = 3 | 3/3 = 1 | 1 |
| O | 16 | 48 | 48/16 = 3 | 3/3 = 1 | 1 |
| H | 1 | 9 | 9/1 = 9 | 9/3 = 3 | 3 |
So the empirical formula of the compound is NH2OH.
APPEARS IN
RELATED QUESTIONS
Explain the terms empirical formula and molecular formula.
Give the empirical formula of C2H2
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)
Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.
Calculate the percentage of water of crystallization in CuSO4. 5H2O
(H = 1, O = 16, S = 32, Cu = 64)
Find the percentage of mass water in Epsom salt MgSO4.7H2O.
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
Give the empirical formula of C6H18O3
Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.
