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Question
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
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Solution
| Element | Atomic mass | Percentage | Relative number of moles | Simplest mole ratio | Whole number ratio |
| N | 14 | 42 | 42/14 = 3 | 3/3 = 1 | 1 |
| O | 16 | 48 | 48/16 = 3 | 3/3 = 1 | 1 |
| H | 1 | 9 | 9/1 = 9 | 9/3 = 3 | 3 |
So the empirical formula of the compound is NH2OH.
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