Advertisements
Advertisements
Question
Derive a relationship between S.I. and C.C.S. unit of work
Advertisements
Solution
SI unit of work = Nm(Joule)
CGS units of work = dyne-cm (erg)
`1 N = 10^5 "dyne"`
`1 m = 10^2 cm`
`:. 1 "Joule" = 10^5 xx 10^2 "dynecm" = 10^7 erg`
APPEARS IN
RELATED QUESTIONS
Write the expression for work done by a force.
A water pump raises 50 litres of water through a height of 25 m in 5 s. Calculate the power of the pump required.
(Take g = 10 N kg-1 and density of water = 1000 kg m-3)
Its moment of a force scalar or a vector quantity?
State the conditions of equilibrium for a rigid body.
Complete the following sentences:
Joule is the unit of .......
Name the physical quantity associated with the 'rate of doing work'.
A bullet is of mass 'm' g and is moving with a velocity 'v' m/s. Find the kinetic energy of the bullet when
(a) The mass is doubled,
(b) The velocity is tripled.
A man climbs a slope and another walks same distance on level road. Which of the two expends more energy and why?
A bucketful of water is to be drawn from a well ______ will be done when a ______ is applied to do this because there will be a ______ of water.
(displacement, work, force)
State whether work is done or not, by writing yes or no, in the following case:
A man pushes a wall.
