Advertisements
Advertisements
प्रश्न
Derive a relationship between S.I. and C.C.S. unit of work
Advertisements
उत्तर
SI unit of work = Nm(Joule)
CGS units of work = dyne-cm (erg)
`1 N = 10^5 "dyne"`
`1 m = 10^2 cm`
`:. 1 "Joule" = 10^5 xx 10^2 "dynecm" = 10^7 erg`
APPEARS IN
संबंधित प्रश्न
In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east, as shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive or zero.

A boy of mass 40 kg climbs up the stairs and reaches the roof at a height 8 m in 5 s. Calculate:
- the force of gravity acting on the boy,
- the work done by him against the force of gravity,
- the power spent by boy. (Take g = 10 m s-2)
A machine raises a load of 750 N through a height of 16 m in 5 s. calculate:
- energy spent by machine,
- power at which the machine works.
In which of the following case the work done by a force will be maximum : when the angle between the direction of force and direction of motion is 0° or 90°?
List any six forms of energy and write a short note on each of them.
State the energy changes which take place when A stone dropped from the top of a cliff reaches the ground after some time.
A is a push or a pull ______.
A force can cause an object to change its ______.
