Advertisements
Advertisements
प्रश्न
Derive a relationship between S.I. and C.C.S. unit of work
Advertisements
उत्तर
SI unit of work = Nm(Joule)
CGS units of work = dyne-cm (erg)
`1 N = 10^5 "dyne"`
`1 m = 10^2 cm`
`:. 1 "Joule" = 10^5 xx 10^2 "dynecm" = 10^7 erg`
APPEARS IN
संबंधित प्रश्न
Why is a jack screw provided with a long arm?
In which of the following cases, is work being done?
(i) A man pushing a wall.
(ii) a coolie standing with a load of 12 kgf on his head.
(iii) A boy climbing up a staircase.
A boy weighing 25 kgf climbs up from the first floor at height 3 m above the ground to the third floor at height 9m above the ground. What will be the increase in his gravitational potential energy? (Take g = 10 N kg -1)
A body of mass 0.5 kg travels on straight line path with velocity v = (3x2 + 4) m/s. The net work done by the force during its displacement from x = 0 tox = 2 m is ______.
