Advertisements
Advertisements
प्रश्न
Derive a relationship between S.I. and C.C.S. unit of work
Advertisements
उत्तर
SI unit of work = Nm(Joule)
CGS units of work = dyne-cm (erg)
`1 N = 10^5 "dyne"`
`1 m = 10^2 cm`
`:. 1 "Joule" = 10^5 xx 10^2 "dynecm" = 10^7 erg`
APPEARS IN
संबंधित प्रश्न
A force of 30 N acts on a body and moves it through a distance of 5 m in the direction of force. Calculate the work done by the force.
A weight lifter lifted a load of 200 kgf to a height of 2.5 m in 5 s. Calculate:
- the work done, and
- the power developed by him. Take g = 10 N kg-1
Name the forms of energy which a wound-up watch spring possesses.
When is the work done by a force on a body : (a) positive, (b) negative, and (c) zero?
State the conditions of equilibrium for a rigid body.
A bullet is of mass 'm' g and is moving with a velocity 'v' m/s. Find the kinetic energy of the bullet when
(a) The mass is doubled,
(b) The velocity is tripled.
A canon ball of mass 500g is fired with a speed of 15m/s-1. Find: its momentum.
In the following case write yes, if the work is being done and no if no work is being done.
A boy climbing up a staircase.
